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Topic:
-1 = 1
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Topic: -1 = 1 (Read 968 times)
Mike
Jackass In Charge
Posts: 11248
Karma: +168/-32
Ex Asshole - a better and more caring person.
-1 = 1
«
on:
June 13, 2006, 05:56:42 PM »
Given
i = √-1
√a * √b = √(a*b)
-1 = i
2
= (√-1)*(√-1) = √(-1 * -1) = √1 = 1
Proof that -1 = 1 :P
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Ken Fitlike
Jackass V
Posts: 1568
Karma: +25/-22
Ebeneezer McScrooge
Re: -1 = 1
«
Reply #1 on:
June 13, 2006, 06:10:16 PM »
-1 = i^2 ????
edit: er - I mean: √a * √b = √(a*b) is true for some prescribed limit of values for a and b and I suspect the roots of negative numbers aren't included.
But then, what I know about maths can be scribbled down on the back of a postage stamp.
«
Last Edit: June 13, 2006, 08:12:56 PM by Ken Fitlike
»
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And what rough beast, its hour come round at last,
Slouches towards Bethlehem to be born?.
Mike
Jackass In Charge
Posts: 11248
Karma: +168/-32
Ex Asshole - a better and more caring person.
Re: -1 = 1
«
Reply #2 on:
June 13, 2006, 08:22:53 PM »
well if i = √-1 then you square both sides i
2
= -1 right?
And you are spot on: √a * √b = √(a*b) is only valid for a>=0, b >= 0
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Ken Fitlike
Jackass V
Posts: 1568
Karma: +25/-22
Ebeneezer McScrooge
Re: -1 = 1
«
Reply #3 on:
June 13, 2006, 09:36:00 PM »
>>well if i = √-1 then you square both sides i2 = -1 right?<<
Yes, I got that, hence my edit - 2 hours later.
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And what rough beast, its hour come round at last,
Slouches towards Bethlehem to be born?.
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Topic:
-1 = 1